SOLUTION: 1) Expand​ the series and evaluate.
7
Σ -3(2)^k-1
k=1
enter only the sum.
2) Find the sum of the series.
13
Σ k
k=1
3) Expand the series and evaluate.
Algebra ->
Sequences-and-series
-> SOLUTION: 1) Expand​ the series and evaluate.
7
Σ -3(2)^k-1
k=1
enter only the sum.
2) Find the sum of the series.
13
Σ k
k=1
3) Expand the series and evaluate.
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Question 1085710: 1) Expand the series and evaluate.
7
Σ -3(2)^k-1
k=1
enter only the sum.
2) Find the sum of the series.
13
Σ k
k=1
3) Expand the series and evaluate.
8
Σ (-1)^k(4k-5)
k=5
enter only the sum.
4) Find the sum of the first six terms of the geometric series in which a3 is -18 and a6 is 486.
5) Evaluate.
s5 for 2500+2000+1600+1280+...
6) Evaluate.
13
Σ 12k-62
k=3
7) Evaluate.
8
Σ 6(-2)^k
k=1
enter only the sum.
8) Evaluate.
9
Σ 3k+4
k+1
enter only the sum.
9) Determine which expressions can be used to show the following series in summation notation.
- 1/2 + - 1/4 +(- 1/6) + 1/8 +(- 1/10)
10) Evaluate.
s21 for 23+20+17+14+...
enter only the sum. Answer by Alan3354(69443) (Show Source):
