SOLUTION: A rectangular swimming pool in a resort in Tagaytay City is twice as long as it is wide. A small concrete walkway surrounds the pool. The alkway is a constant 2 feet wide and has a
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-> SOLUTION: A rectangular swimming pool in a resort in Tagaytay City is twice as long as it is wide. A small concrete walkway surrounds the pool. The alkway is a constant 2 feet wide and has a
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Question 1085707: A rectangular swimming pool in a resort in Tagaytay City is twice as long as it is wide. A small concrete walkway surrounds the pool. The alkway is a constant 2 feet wide and has an area of 196 square feet. Find the dimensions of the pool.
You can put this solution on YOUR website! L = 2W
walkway = 2 feet. Added to the pool, it makes the outer rectangle.
196 = area of outer rectangle - area inner rectangle (pool)
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Outer rectangle: (W+4)(2W+4) = 2W^2+12W+16
Pool: W*2W = 2W^2
Walkway: (2W^2+12x+16)-(2W^2)
= 12W+16
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12W+16 = 196
12W = 180
W = 15
Now you know the width, you can solve for length:
L = 2W = 30