SOLUTION: By how much does the area of square of side (3x-7)centimeter exceed the area of a rectangle (x+5)centimeter long by (x-3)centimeter wide?

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Question 1085456: By how much does the area of square of side (3x-7)centimeter exceed the area of a rectangle (x+5)centimeter long by (x-3)centimeter wide?
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
A sq=(3x-7)^2=9x^2-42x+49
A rectangle=(x+5)(x-3)=x^2+2x-15
The difference is 8x^2-44x+64