SOLUTION: n=3 2 and 4i are zeros f(-1)=51

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Question 1085311: n=3 2 and 4i are zeros f(-1)=51
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
if 4i is a root, -4i is also a root
It is a fourth degree polynomial
(x-3)(x-2)(x^2+16) is the polynomial or (x^2-5x+6)(x^2+16)
That is x^4+16x^2-5x^3-80x+6x^2+96
x^4-5x^3+22x^2-80x+96
multiply the whole thing by a
a(x^4-5x^3+22x^2-80x+96)=51 when x=-1
a(1+5+22+80-96)=51
a(12)=51
a=4.25 or 17/4
graph%28300%2C300%2C-10%2C10%2C-100%2C100%2C4.25%28x%5E4-5x%5E3%2B22x%5E2-80x%2B96%29%29