Question 1085303: The students of a certain class agreedbto share $2800 expense required to paint the whole class.Five students couldn't contribute to that collection.So other students agreed to contribute the short amount equally.If every student who agreed to pa,happened to pay$ 10 more than what they previously paid,find the total number of the students in the class.?
Found 3 solutions by Boreal, josmiceli, jorel1380:
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! x students in the whole class
2800/x is the amount per student.
If 5 students couldn't contribute, the amount per student is 2800/(x-5)
We know that 2800/x is $10 less than 2800/(x-5)
2800/x + $10 =2800/(x-5)
multiply by x(x-5)
2800(x-5)+10(x*(x-5))=2800x
2800x-14000+10x^2-50x=2800x
10x^2-50x-14000=0
x^2-5x-1400=0
(x-40)(x+35)=0; x=40, only positive root.
x=40 students, each would have paid $70
x-5=35 students, and each will have to pay $80, $10 more. Both products are $2800.
Answer by josmiceli(19441)  (Show Source):
Answer by jorel1380(3719)  (Show Source):
You can put this solution on YOUR website! Let n be the number of students, and m be their contribution. Then
m=2800/n and
m+10=2800/(n-5)
((2800/n)+10)(n-5)=2800
Solve for n. 🙂🙂🙂🙂
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