SOLUTION: A number consists of two digits sum of its digit is 15. if the place of digits are interchange, then the number obtained is 9 less than the original number. find the orig

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Question 1085222: A number consists of two digits sum of its digit is 15.

if the place of digits are interchange, then the number obtained is 9 less than the original number.

find the original number

Found 3 solutions by josmiceli, addingup, Theo:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +u+ = the units digit
Let +t+ = the tens digit
---------------------------
(1) +t+%2B+u+=+15+
(2) +10u+%2B+t+=+10t+%2B+u+-+9+
-------------------------------
(2) +10u+-+u+%2B+t+-+10t+=+-9+
(2) +-9t+%2B+9u+=+-9+
(2) +-t+%2B+u+=+-1+
----------------------
Add (1) and (2)
(1) +t+%2B+u+=+15+
(2) +-t+%2B+u+=+-1+
-------------------
+2u+=+14+
+u+=+7+
and
(1) +t+%2B+u+=+15+
(1) +t+%2B+7+=+15+
(1) +t+=+8+
---------------------
The original number is 87
-----------------------------
check:
Interchange the digits: 78
+78+=+87+-+9+
+78+=+78+
OK

Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
digit one: x
digit two: y
-------------------------
x+y = 15 (1)
if interchanged:
10y+x = 10x+y-9
10y+x-10x-y = -9
9y-9x = -9 divide all sides by 9:
y-x = -1 (2)
Add (1) and (2):
x+y = 15
+
-x+y = -1
__________
0+2y = 14
y = 7
the sum of the two digits = 15, so 15-7 = 8
----------------------
Check:
sum of the digits: 8+7 = 15
interchanged 9 less: 87-78 = 9 correct

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!

you are told:

A number consists of two digits sum of its digit is 15.

if the place of digits are interchanged, then the number obtained is 9 less than the original number.

and you are asked:

find the original number

let ab be the original number.

the value of ab is 10 * a + b.

if the original number is ab, then the number with the digits interchanged would be ba.

the value of the number would then be 10 * b + a.

you are told that the sum of the digits is 15 and, if the place of the digits are interchanged, then the number obtained is 9 less than the original number.

this gets you a + b = 15 and 10b + a = 10a + b - 9

you have 2 equations that need to be solved simultaneously.

they are:

a + b = 15

10b + a = 10a + b - 9


in the first equation, solve for b to get b = 15 - a

in the second equation, replace b with 15 - a to get:

10 * (15 - a) + a = 10a + (15 - a) - 9

simplify to get:

150 - 10a + a = 10a + 15 - a - 9

combine like terms to get:

150 - 9a = 9a + 6

subtract 6 from both sides of the equation and add 9a to both sides of the equation to get 144 = 18a.

divide both sides of the equation by 18 to get 144/18 = a

solve for a to get a = 144/18 = 8

since a + b = 15, then b must be equal to 7.

the original number is ab which is 87.

the new number is ba which is equal to 78 which is equal to 9 less than 87.

the sum of the digits is 15.

all the requirements of the problem have been satisfied, so the solution looks good.