SOLUTION: A kindergarten class is going to a play with some teachers. Tickets cost $6 for children
and $15 for adults. The number of tickets sold amount to $231. How many teachers
and chil
Question 1085201: A kindergarten class is going to a play with some teachers. Tickets cost $6 for children
and $15 for adults. The number of tickets sold amount to $231. How many teachers
and children went to the play? Found 3 solutions by emathwiz, josgarithmetic, MathTherapy:Answer by emathwiz(15) (Show Source):
You can put this solution on YOUR website! This is systems of equations so lets write this out and see which method of solving works the best. Let's let children ticket amount be (c) and adult ticket amount be (a).
231 = 6c + 15a Neither 6 nor 15 go into 231 so let's think about how to tell if a number is divisible by 6 or 15. 6 means it is divisible by 3 and 2 and 15 means it needs to be divisible by 3 and 5 so looking at 231 which is divisible by 3 (because digits add up to a multiple of 3) we can play around and tear apart this equation since a multiple of 3 stays one as long as another multiple of 3 is applied to it. So just look for two numbers within 231 that are multiples of 6 and 15
216+15=6c + 15a
c = 36
a = 1
Sorry for the weirdest solution ever!
You can put this solution on YOUR website! A kindergarten class is going to a play with some teachers. Tickets cost $6 for children
and $15 for adults. The number of tickets sold amount to $231. How many teachers
and children went to the play?
No unique solution. Number of teachers/adults start at 1, and ends at 15, so that's 8 combinations.
Why don't you state the exact problem, word-for-word? Also, why is there a reference to TEACHERS, and then those became ADULTS?