SOLUTION: How many kilograms of hard candy that cost $7.50 per kilogram must be mixed with 24 kilograms of jelly beans that cost $3.25 per kilogram to make a mixture that sells for $4.50 per
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: How many kilograms of hard candy that cost $7.50 per kilogram must be mixed with 24 kilograms of jelly beans that cost $3.25 per kilogram to make a mixture that sells for $4.50 per
Log On
Question 1085078: How many kilograms of hard candy that cost $7.50 per kilogram must be mixed with 24 kilograms of jelly beans that cost $3.25 per kilogram to make a mixture that sells for $4.50 per kilogram? Answer by ikleyn(52786) (Show Source):
Your equation is
= 4.50.
Simplify it by multiplying both sides by (x + 3.75). You will get
7.50*x + 24*3.75 = 4.50*((x+3.75).
Simplify further and solve for x, which is the amount of hard candy to be mixed, in kilograms.
