SOLUTION: One solution, Solution A, is 70% water and 30% acid. Another solution, Solution B, is 40% water and 60% acid. How many liters of each of these solutions would be required to make 3

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: One solution, Solution A, is 70% water and 30% acid. Another solution, Solution B, is 40% water and 60% acid. How many liters of each of these solutions would be required to make 3      Log On


   

Question 1084999: One solution, Solution A, is 70% water and 30% acid. Another solution, Solution B, is 40% water and 60% acid. How many liters of each of these solutions would be required to make 300 liters of a solution which is 60% water and 40% acid?
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
Solution B is 60% acid, and solution A is 30% acid. Let b be for solution B, then solution A is (300-b). So:
.6b+.3(300-b)=300(.4)
.3b+90=120
Solve for b.
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