SOLUTION: I am doing permutation problems using the formula nPr = n!/(n-r)!. The problem I am having difficulty with is nP3 = 24. I can get it this far:
n(n-1)(n-2)...2x1 / (n-3)(n-4)...2
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-> SOLUTION: I am doing permutation problems using the formula nPr = n!/(n-r)!. The problem I am having difficulty with is nP3 = 24. I can get it this far:
n(n-1)(n-2)...2x1 / (n-3)(n-4)...2
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Question 108469: I am doing permutation problems using the formula nPr = n!/(n-r)!. The problem I am having difficulty with is nP3 = 24. I can get it this far:
n(n-1)(n-2)...2x1 / (n-3)(n-4)...2x1 = 24
n(n-1)(n-2) = 24 Then I'm not sure how to finish. Please help. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! nP3 = 24
n!/(n-3)! = 24
n(n-1)(n-2)=24
n(n^2-3n+2)=24
n^3-3n^2+2n-24=0
I graphed this and found n=4 is a solution.
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Checking:
4P3 = 4!/(4-3)! = 4!/1! = 4! = 24
OK
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Cheers,
Stan H.
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