SOLUTION: In the equation log(3)63 - log(3)7 = log(6)x, what is the real value of x? I've found that log(6)x = 9, but I don't know what to do from here.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: In the equation log(3)63 - log(3)7 = log(6)x, what is the real value of x? I've found that log(6)x = 9, but I don't know what to do from here.      Log On


   

Question 1084378: In the equation log(3)63 - log(3)7 = log(6)x, what is the real value of x?
I've found that log(6)x = 9, but I don't know what to do from here.
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
In the equation log(3)63 - log(3)7 = log(6)x, what is the real value of x?
I've found that log(6)x = 9
--------
If it's
log%283%2C63%29+-+log%283%2C7%29+=+log%286%2Cx%29
log%283%2C63%2F7%29+=+log%286%2Cx%29
log%283%2C9%29+=+log%286%2Cx%29
log%286%2Cx%29+=+2
log%286%2Cx%29+=+log%286%2C6%5E2%29
x = 36

Answer by ikleyn(52866) About Me  (Show Source):
You can put this solution on YOUR website!
.
You definitely need to learn more on logarithms.


On logarithms and their properties, see the lessons
    - WHAT IS the logarithm
    - Properties of the logarithm
    - Change of Base Formula for logarithms
    - Solving logarithmic equations
    - Using logarithms to solve real world problems
in this site.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Logarithms".