SOLUTION: what is y when (2, -15), (5, y), m= 4/5
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Question 108429
This question is from textbook
McDougal Littell Algebra 1
:
what is y when (2, -15), (5, y), m= 4/5
This question is from textbook
McDougal Littell Algebra 1
Answer by
checkley71(8403)
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4/5=.8
m=(y2-y1)/x2-x1)
.8=(y+15)/(5-2)
.8=(y+15)/3 now cross multiply
y+15=3*.8
y+15=2.4
y=2.4-15
y=12.6 answer.
proof
.8=(12.6-15)/(5-2)
.8=2.4/3
.8=.8