Question 1084176: An ordinary (fair) die is a cube with the numbers
1
through
6
on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
Compute the probability of each of the following events:
Event
A
: The sum is greater than
9
.
Event
B
: The sum is divisible by
4
.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! The probabilities
sum is 2: 1/36
sum is 3: 2/36
(others omitting the denominator)
4:3
5:4
6:5
7:6
8:5
9:4
10:3
11:2
12:1
Therefore, greater than 9 is 6/36=1/6
Divisible (evenly, I assume) by 4, is 3,6,9,12, or 12/36=1/3
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