SOLUTION: solve the following systems by substitution
5x-2y=-5
y-5x=3
5x-2(5+3)=-5 y=5(3)+3
5x-10x+3=-5 =15+3
-5x=-15 =18
x=3
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-> SOLUTION: solve the following systems by substitution
5x-2y=-5
y-5x=3
5x-2(5+3)=-5 y=5(3)+3
5x-10x+3=-5 =15+3
-5x=-15 =18
x=3
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Question 108403: solve the following systems by substitution
5x-2y=-5
y-5x=3
5x-2(5+3)=-5 y=5(3)+3
5x-10x+3=-5 =15+3
-5x=-15 =18
x=3
Just double checking to see if I did these right. Answer by elima(1433) (Show Source):
You can put this solution on YOUR website! Not quite;
5x-2y=-5
y-5x=3
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we will go ahead and solve the second equation for y;
y-5x=3
y=3+5x
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now put that in for y in the first equation;
5x-2(3+5x)=-5
5x-6-10x=-5
-6-5x=-5
-5x=-5+6
-5x=1
x=-1/5
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Now plug that in the equation and solve for y;
5(-1/5)-2y=-5
-5/5-2y=-5
-1-2y=-5
-2y=-4
y=2
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:)
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