SOLUTION: Hi I'm stuck on this question, I have tried looking at other resources for help and asked my parents but no one can help, I would really appreciate it if somebody could help. A

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Question 1083471: Hi I'm stuck on this question, I have tried looking at other resources for help and asked my parents but no one can help, I would really appreciate it if somebody could help.
A quadrilateral has sides of length x cm, x + 3cm, x − 4cm and 2xcm. What is the perimeter of
the quadrilateral in terms of x?

Found 2 solutions by Theo, jim_thompson5910:
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
the quadrilateral has sides whose lengths are:

x
x+3
x-4
2x

the perimeter of the quadrilateral is the sum of the length of each side.

therefore, the perimeter would be x + x + 3 + x - 4 + 2x

combine like terms and the perimeter becomes 5x - 1

how does this work?

let's assume x is equal to 10.

when x = 10, the length of each side would be:

x = 10
x+3 = 13
x-4 = 6
2x = 20

the perimeter would be 10 + 13 + 6 + 20 = 49

we said the perimeters was 5x - 1 in terms of x.

when x = 10, 5x - 1 = 49

your solution is that the perimeter is equal to 5x - 1 in terms of x.


Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
side1 = x
side2 = x+3
side3 = x-4
side4 = 2x

Add up the four sides to get the perimeter P

P = (side1) + (side2) + (side3) + (side4)
P = (x) + (x+3) + (x-4) + (2x)
P = x + x + 3 + x - 4 + 2x
P = (x+x+x+2x) + (3-4)
P = 5x - 1

Answer: 5x - 1