SOLUTION: An urn contains 4 pink marbles and 4 green marbles. Two marbles are drawn at random. What is the probability that the first one is pink and the second one is green if the marbles a
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-> SOLUTION: An urn contains 4 pink marbles and 4 green marbles. Two marbles are drawn at random. What is the probability that the first one is pink and the second one is green if the marbles a
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Question 1083405: An urn contains 4 pink marbles and 4 green marbles. Two marbles are drawn at random. What is the probability that the first one is pink and the second one is green if the marbles are drawn
(a) with replacement (b) without replacement
You can put this solution on YOUR website! Probability is the number of possible outcomes desired divided by the number of possible total outcomes. For independent events like this, this is:
P(A and B) = (P(A))*(P(B))
:
With replacement:
P(pink and green)=(4/11)(4/11) = 16/121 = 0.1322 or 13.22%
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Without replacement:
P(pink and green)=(4/11)(4/10) = 16/110 = 0.14545 or 14.545%
