SOLUTION: What is the least integer greater than log3 38?

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Question 1083245: What is the least integer greater than log3 38?
Found 4 solutions by Boreal, Edwin McCravy, MathLover1, KMST:
Answer by Boreal(15235) About Me  (Show Source):
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The integer is 4
log 3 (38) is 3^x=38
when x=3, 3^3=27
when x=4, 3^4=81
log 3 (81)=4

Answer by Edwin McCravy(20064) About Me  (Show Source):
You can put this solution on YOUR website!
What is the least integer greater than log338?
I think this is the way your teacher expects you to find the
answer:

log338 means 

the exponent to which 3 must be raised to give 38.
So to find the least integer greater than that exponent, 
we begin by trying integer exponents of 3 until we find 
the smallest integer such that when 3 is raised to that 
power, the answer is greater that 38.  

We begin by trying exponent 1:

31 = 3  <--smaller than 38, so we try the next integer 2.

32 = 3×3 = 9  <--still smaller than 38, so we try 3

33 = 3×3×3 = 27  <--still smaller than 38, so we try 4

34 = 3×3×3×3 = 81  <--that's it!  for 81 is greater than 38

So the least integer greater than log338 is 4.

Edwin

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

log%283+%2C38%29
=log%2838%29%2Flog%283%29
=3.31107361
so, the least integer greater than log%283+%2C38%29 is 4

Answer by KMST(5328) About Me  (Show Source):
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3%5E3=3%2A3%2A3=9%2A3=27 and 3%5E4=3%2A3%2A3%2A3=9%2A9=81 , so 3%5E3%3C38%3C3%5E4
and that means
3%3Clog%283%2C38%29%3C4 ,
so the least integer greater than log%283%2C38%29 is 4 .