SOLUTION: Please help me find all real soultions for this equation.
{{2y^2=15+y}}}
The teacher said there are two answers which are 3 and -5/2. I can not get to either of these answers.
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-> SOLUTION: Please help me find all real soultions for this equation.
{{2y^2=15+y}}}
The teacher said there are two answers which are 3 and -5/2. I can not get to either of these answers.
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Question 108322: Please help me find all real soultions for this equation.
{{2y^2=15+y}}}
The teacher said there are two answers which are 3 and -5/2. I can not get to either of these answers.
Thank you Found 2 solutions by stanbon, MathLover1:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! find all real soultions for this equation.
2y^2=15+y
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2y^2-y-15=0
Using the AC Method of factoring:
2y^2-6y+5y-15=0
2y(y-3)+5(y-3)=0
(y-3)(2y+5)=0
y-3=0 or 2y+5=0
y=3 or y=-5/2
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Cheers,
Stan H.
You can put this solution on YOUR website! ....move all terms to the left
now use quadratic formula:
your , , and
so, you will have:
....first answer
....divide both and by ....second answer
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