SOLUTION: If y=logbase2(x+sqrtx^2+1),then2^y-2^-y=

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Question 1083092: If y=logbase2(x+sqrtx^2+1),then2^y-2^-y=
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Assume the problem is:
If y=log%282%2C%28x%2Bsqrt%28x%5E2%2B1%29%29%29, then 2%5Ey+-+2%5E%28-y%29
We can write 2%5Ey+-+2%5E%28-y%29 as 2%5Ey+-+1%2F2%5Ey
the exponent equiv of logs
2%5Ey=%28x%2Bsqrt%28x%5E2%2B1%29%29, therefore
:
2%5Ey+-+1%2F2%5Ey = %28x%2Bsqrt%28x%5E2%2B1%29%29 - 1%2F%28x%2Bsqrt%28x%5E2%2B1%29%29,