SOLUTION: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.

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Question 108306: The length of a rectangle is 2 cm more than twice its width.
If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
l=2w+2
perimeter=2l+2w
52=2(2w+2)+2w
52=4w+4+2w
6w=52-4
6w=48
w=48/6
w=8 cm.
l=2*8+2
l=16+2
l=18 cm.
proof
52=2*18+2*8
52=36+16
52=52