Question 1083054: A sample of 44 observations is selected from one population with a population standard deviation of 4.9. The sample mean is 102.0. A sample of 45 observations is selected from a second population with a population standard deviation of 3.8. The sample mean is 100.6. Conduct the following test of hypothesis using the 0.02 significance level.
I need help with # b the intervals and e the p-value
a. This is a -tailed test.
b.
State the decision rule. (Negative values should be indicated by a minus sign. Round your answers to 2 decimal places.)
The decision rule is to reject H0 if z is outside the interval (),().
c. Compute the value of the test statistic. (Round your answer to 2 decimal places.)
Value of the test statistic 1.51
d. What is your decision regarding H0?
Do Not reject
e. What is the p-value? (Round your answer to 4 decimal places.)
p-value
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! It is a 2-tailed test.
Reject Ho if |z|>2.33. The absolute value of z is a nice shortcut to say if z is <-2.33 or >+2.33 one will reject Ho.
z=1.51
p-value is 0.1326.
With a calculator, that comes up. Without, one looks up the z-value for 1.51 in a table and that is one sided probability. For two sided probability, multiply the z-value by 2.
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