SOLUTION: The average speed of an express train is 40 km/h faster than the average speed of a bus. To travel 1200km, the bus requires 50% more time than the train. Determine the average sp

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: The average speed of an express train is 40 km/h faster than the average speed of a bus. To travel 1200km, the bus requires 50% more time than the train. Determine the average sp      Log On


   



Question 1083006: The average speed of an express train is 40 km/h faster than the average speed of a bus. To
travel 1200km, the bus requires 50% more time than the train. Determine the average
speeds of the train and the bus

Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52798) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let B be average speed of the bus, in kilometers per hour.

Then the average speed of the train is (B+40) km/h, according to the condition.


The bus covers 1200 km in 1200%2FB hours.
The train covers 1200 km in 1200%2F%28B%2B40%29 hours.

The condition says that to travel 1200 km, the bus requires 50% more time than the train. It means that

1200%2FB = 1.5%2A%281200%2F%28B%2B40%29%29.

It is your equation to find the unknown B.


Simplify it step by step, first canceling 1200 in both sides:

1%2FB = 1.5%2F%28B+%2B+40%29  ---->

B + 40 = 1.5*B  (after cross multiplying)  ---->

0.5B = 40  ---->  B = 40%2F0.5 = 80 km/h.


Thus the bus speed is 80 km/h.

Then the train speed is (B+40) = 80 + 40 = 120 km/h.


Check.  Bus' time = {{1200/80}}} = 15 hours.

        Train's time = 1200%2F120 = 10 hours.


Answer.  The bus' speed = 80 km/h.  The train' speed = 120 km/h.


Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
              SPEED       TIME       DISTANCE 

TRAIN          r+40       t            1200

BUS            r          t+t/2        1200


r%283t%2F2%29=1200
1200%282%2F3%29%281%2Fr%29=t
t=800%2Fr

-
%28r%2B40%29%28800%2Fr%29=1200

%28r%2B40%29%2Fr=12%2F8
%28r%2B40%29%2Fr=3%2F2
2%28r%2B40%29=3r
2r%2B80=3r
r=80 --- r%2B40=120
-
Bus, 80 km/h
Train, 120 km/h
(t=10 hours for the train)