SOLUTION: What is the maximum allowable error in the edge of a cube to be used to contain 10 cubic meters if the error in the volume is not to exceed 0.015 cubic meter?

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Question 1082947: What is the maximum allowable error in the edge of a cube to be used to contain 10 cubic meters if the error in the volume is not to exceed 0.015 cubic meter?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The volume of a cube is,
V=s%5E3
The maximum volume allowed is,
V%5Bmax%5D=10.015
So,
s%5E3=10.015
s=2.155511m
If it was perfect,
s%5E3=10
s%5Bp%5D=2.154435
So then,
E=abs%28s%5Bp%5D-s%29
E=abs%282.154435-2.155511%29
E=0.001077
So the edge must be,
s%5BI%5D=2.154+%2B-+0.001m