SOLUTION: A father is 3 times as old as his son and his daughter is 3yrs younger than the son. If the sum of their ages 3 yrs ago was 63, find the present age of the father

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Question 1082684: A father is 3 times as old as his son and his daughter is 3yrs younger than the son. If the sum of their ages 3 yrs ago was 63, find the present age of the father
Answer by ikleyn(52784) About Me  (Show Source):
You can put this solution on YOUR website!
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Let S be the son's present age.
Then the daughter's age is S-3 years now and the father's age is 3S years now.


3 years ago the son age was (S-3), the daughter's age was (S-6) and the father's age was 3S - 3.


So, your equation is 

(S-3) + (S-6) + (3S-3) = 63 .

Simplify and solve for S:

5S - 12 = 63  --->  5S = 75  ---->  S = 75%2F5 = 15.


So, the son is 15 years old now.

From this point, complete the solution on your own.

There is a bunch of lessons on age word problems
    - Age problems and their solutions
    - A fresh formulation of a traditional age problem
    - Really intricate age word problem
    - Selected age word problems from the archive
in this site.

Read them and become an expert in solving age problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Age word problems".