SOLUTION: What is the equation of the following graph?
ellipse through the points (1, negative 2), (0, 1), (negative 1, negative 2) and (0, negative 5)
pic http://prntscr.com/fboqx0
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Quadratic-relations-and-conic-sections
-> SOLUTION: What is the equation of the following graph?
ellipse through the points (1, negative 2), (0, 1), (negative 1, negative 2) and (0, negative 5)
pic http://prntscr.com/fboqx0
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Question 1082607: What is the equation of the following graph?
ellipse through the points (1, negative 2), (0, 1), (negative 1, negative 2) and (0, negative 5)
pic http://prntscr.com/fboqx0 Answer by natolino_2017(77) (Show Source):
You can put this solution on YOUR website! let (x-h)^2/a^2 + (y-k)^2/b^2 = 1. the general equation.
we have to solve the system:
1) (1-h)^2/a^2 + (2+k)^2/b^2 = 1
2) h^2/a^2 + (1-k)^2/b^2 =1
3) (1+h)^2/(a^2) + (2+k)^2/b^2 = 1
4) h^2/a^2 + (5+k)^2/b^2 = 1
3) - 1) 4h/a^2 =0 so h = 0.
4) - 2) (24 + 12k)/b^2 = 0, so k =-2.
replacing on 1) 1/a^2 = 1, so a^2 = 1.
replacing on 2) 9/b^2 = 1, so b^2 = 9.
Answer: x^2 + (y+2)^2/9 = 1
@natolino_
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