SOLUTION: If {{{ sin(x) + cos(x) = 1/2 }}}, compute {{{ sin(x)cos(x) }}} . (You may work on both sides.)

Algebra ->  Trigonometry-basics -> SOLUTION: If {{{ sin(x) + cos(x) = 1/2 }}}, compute {{{ sin(x)cos(x) }}} . (You may work on both sides.)      Log On


   



Question 1082320: If +sin%28x%29+%2B+cos%28x%29+=+1%2F2+, compute +sin%28x%29cos%28x%29+ . (You may work on both sides.)
Found 2 solutions by ikleyn, Edwin McCravy:
Answer by ikleyn(52812) About Me  (Show Source):
You can put this solution on YOUR website!
.
Square both sides of your equation. You will get

%28sin%28x%29+%2B+cos%28x%29%29%5E2 = 1%2F4,

sin%5E2%28x%29+%2B+2%2Asin%28x%29%2Acos%28x%29+%2B+cos%5E2%28x%29 = 1%2F4,


1+%2B+2%2Asin%28x%29%2Acos%28x%29 = 1%2F4,

2*sin(x)*cos(x) = 1%2F4-1,  

sin(x)*cos(x) = -3%2F8               

Answer. sin(x)*cos(x) = -3%2F8.



Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!

+sin%5E%22%22%28x%29+%2B+cos%5E%22%22%28x%29+=+1%2F2+

Square both sides of the equation

+%28sin%5E%22%22%28x%29+%2B+cos%5E%22%22%28x%29%5E%22%22%29%5E2+=+%281%2F2%29%5E2+



Use FOIL on the left



The two middle terms are like terms, so they combine:



Swap the 2nd and 3rd term on the left



Recall the Pythagorean identity sin%5E2%28theta%29%2Bcos%5E2%28theta%29=1

1+%2B+2sin%5E%22%22%28x%29cos%5E%22%22%28x%29%5E%22%22++=+1%2F4+

Clear the fraction by multiplying through by 4

4+%2B+8sin%5E%22%22%28x%29cos%5E%22%22%28x%29%5E%22%22++=+1+

Subtract 4 from both sides

8sin%5E%22%22%28x%29cos%5E%22%22%28x%29%5E%22%22++=+-3+

Divide both sides by 8

sin%5E%22%22%28x%29cos%5E%22%22%28x%29%5E%22%22++=+-3%2F8+

Edwin