SOLUTION: solve the log equation 25^(3x)= (1/5)^(3x+1) I did the first step and it's 5^(2)(3x) the thing is that I don't know what to do for the next step.

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: solve the log equation 25^(3x)= (1/5)^(3x+1) I did the first step and it's 5^(2)(3x) the thing is that I don't know what to do for the next step.       Log On


   

Question 1082304: solve the log equation
25^(3x)= (1/5)^(3x+1)
I did the first step and it's 5^(2)(3x)
the thing is that I don't know what to do for the next step.
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
25%5E%283x%29=%281%2F5%29%5E%283x%2B1%29

Review laws or rules for exponents.

%285%5E2%29%5E%283x%29=%285%5E%28-1%29%29%5E%283x%2B1%29
5%5E%286x%29=5%5E%28-3x-1%29
6x=-3x-1%29

9x=-1

x=-1%2F9