Question 1082301: a. How many ways are there of arranging three different math books, five different history books, and four different French books side by side on a shelf if the books of the same subject must be together?
b. How many arrangements of these books are possible if a math book must be on each end and the French books are together?
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website! You have 3 math, they can each be placed on one end, the other, or in the middle, so this is 3!
Now you have 5 hist. books, they can each go in any of 5 positions: 5!
And the French books 4!
Finally, you have books on three subjects, they are grouped but the group can go on the left of the other groups, or the middle, or the right: 3!
3! x 5! x 4! x 3! = 103,680 ways
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