SOLUTION: I need to solve for X. The problem is 2x^2+24=x^2 i then moved the x^2 so that the problem read x^2+24=0 i have to factor it out. I also have to subtract X by five. X is a distance

Algebra ->  Length-and-distance -> SOLUTION: I need to solve for X. The problem is 2x^2+24=x^2 i then moved the x^2 so that the problem read x^2+24=0 i have to factor it out. I also have to subtract X by five. X is a distance      Log On


   

Question 108224: I need to solve for X. The problem is 2x^2+24=x^2 i then moved the x^2 so that the problem read x^2+24=0 i have to factor it out. I also have to subtract X by five. X is a distance so it cannot be a negative number X must be greater than five.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
2x%5E2%2B24=x%5E2
x%5E2%2B24=0
The solution to this equation is a complex number pair.
x%5E2=-24
sqrt%28x%5E2%29=sqrt%28-24%29
x=sqrt%2824%29%2Asqrt%28-1%29 and x=-sqrt%2824%29%2Asqrt%28-1%29
x=2sqrt%286%29i and x=-2sqrt%286%29i
where i=sqrt%28-1%29