Question 1082115: A woman has award robe. containing 5. hats(red,bluegreen,blackandwhite),3pairsofslacks(black, blue and brown), 6 tops (yellow, red, blue, grey, white and purple) and 4 pairs of shoes (high heels, runners, sandals and thongs).
(i) How many different outfits are available to her, no matter how unfashionable some may be?
(ii) What is the probability of choosing an outfit that consists of any hat or top with sandals and a
black pair of slacks?
(iii) If the woman decides to throw out her most unfashionable piece of clothing from each of the four categories above. How many different outfits are available to her now?
(iv) The woman now has considerably fewer available outfits. She wishes to increases the number of available outfits by 33 1 %. What should she buy?
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Found 2 solutions by Boreal, solver91311:
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! (i) 5*3*6*4=360 different outfits.
(ii) 5*1*6*1=30, so 30/360 or 1/12 probability.
(iii)4*2*5*3=120 outfits.
(iv) she needs to increase the number by 1/3 (edited) or by 40, to 160. The way to increase by 1/3 is to increase whatever is 3 to 4, and that would be another pair of shoes. 4*2*5*4=160.
Answer by solver91311(24713)  (Show Source):
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