SOLUTION: Order the following numbers from least to greatest:
A= 2^(1/2)/(4^{1/6)
B= sqrt[12]{128}
C= ({1/(8^1/5)^2
D= sqrt{\frac{4^{-1/(2^{-1} * 8^{-1})
E= sqrt[3]{2^{1/2} * 4^{-1/4}}.
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-> SOLUTION: Order the following numbers from least to greatest:
A= 2^(1/2)/(4^{1/6)
B= sqrt[12]{128}
C= ({1/(8^1/5)^2
D= sqrt{\frac{4^{-1/(2^{-1} * 8^{-1})
E= sqrt[3]{2^{1/2} * 4^{-1/4}}.
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Question 1082098: Order the following numbers from least to greatest:
A= 2^(1/2)/(4^{1/6)
B= sqrt[12]{128}
C= ({1/(8^1/5)^2
D= sqrt{\frac{4^{-1/(2^{-1} * 8^{-1})
E= sqrt[3]{2^{1/2} * 4^{-1/4}}.
Give your answer as a list of capital letters separated by commas. Found 2 solutions by Alan3354, MathLover1:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Order the following numbers from least to greatest:
A= 2^(1/2)/(4^{1/6)
B= sqrt[12]{128}
C= ({1/(8^1/5)^2
D= sqrt{\frac{4^{-1/(2^{-1} * 8^{-1})
E= sqrt[3]{2^{1/2} * 4^{-1/4}}
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Evaluate them, put them in order.
IDK what \ means, or \frac
