SOLUTION: Let line l1 be the graph of 5x + 8y = -9. Line l2 is perpendicular to line l1 and passes through the point (10,10). If line l2 is the graph of the equation y=mx +b, then find m+b.

Algebra ->  Graphs -> SOLUTION: Let line l1 be the graph of 5x + 8y = -9. Line l2 is perpendicular to line l1 and passes through the point (10,10). If line l2 is the graph of the equation y=mx +b, then find m+b.      Log On


   

Question 1082095: Let line l1 be the graph of 5x + 8y = -9. Line l2 is perpendicular to line l1 and passes through the point (10,10). If line l2 is the graph of the equation y=mx +b, then find m+b.
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
L2, -8x%2B5y for the Ax+By=C form makes the lines perpendicular.

-8x%2B5y=-8%2A10%2B5%2A10
-8x%2B5y=-30
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5y=8x-30
highlight%28y=%288%2F5%29x-6%29------slope-intercept form