SOLUTION: solve the log equation log [subscript 7] -3x+ log [subscript 7] 4=2 I got -3/4x

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: solve the log equation log [subscript 7] -3x+ log [subscript 7] 4=2 I got -3/4x      Log On


   

Question 1082048: solve the log equation
log [subscript 7] -3x+ log [subscript 7] 4=2
I got -3/4x
Answer by ikleyn(52795) About Me  (Show Source):
You can put this solution on YOUR website!
.
solve the log equation
log [subscript 7] -3x+ log [subscript 7] 4=2
I got -3/4x
~~~~~~~~~~~~~~~~~ 

log%287%2C%28-3x%29%29  + log%287%2C%284%29%29 = 2  ====>

log%287%2C%28%28-3x%29%2A4%29%29 = 2  ====>

(-3x)*4 = 7%5E2,

-12x = 49  ====>  x = -49%2F12


On logarithms, see a bunch of lessons
    - WHAT IS the logarithm
    - Properties of the logarithm
    - Change of Base Formula for logarithms
    - Solving logarithmic equations
    - Using logarithms to solve real world problems
in this site.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Logarithms".