Question 1082013: The product of two consecutive integers is 13 less than five times their sum. Find the integers.
Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! x, and x+1 are the integers
x^2+x+13=5(x+x+1)
x^2+x+13=10x+5
x^2-9x+8=0
(x-8)(x-1)=0
x=8, 1
8 and 9, product is 72, sum is 17, 5 times the sum is 85.
1 and 2. Product is 2, sum is 3, 5 times the sum is 15.
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