SOLUTION: Write the equation of the line that satisfies the given conditions. Express the final equation in standard form. Contains the point (-7, 8) and is parallel to the line x −

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Question 1081961: Write the equation of the line that satisfies the given conditions. Express the final equation in standard form.
Contains the point (-7, 8) and is parallel to the line x − 6y = 6

Answer by math_helper(2461) About Me  (Show Source):
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Write the equation of the line that satisfies the given conditions. Express the final equation in standard form.
Contains the point (-7, 8) and is parallel to the line x − 6y = 6
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x - 6y = 6 —> +y+=+%281%2F6%29x+-+1+
Compare this to y = mx + b, where m = slope —> m = (1/6)
Parallel lines have equal slope. So the equation of the desired line can be found easily using the point slope form :
+y+-+y%5B0%5D++=+m%28x+-+x%5B0%5D%29+ where (x%5B0%5D+, +y%5B0%5D+) is a point on the line
Plugging in known values:
+y+-+8++=+%281%2F6%29%28x+-+%28-7%29%29+
+++6y+-+48+=+x+%2B+7+
+highlight%28+-x+%2B+6y+=+55%29+
I accept the above as "standard form" because that's what my Calculus book says it is, however some teachers may require the coefficient in front of 'x' to be positive. If so just multiply both sides by -1:
+highlight%28+x+-+6y+=+-55+%29