SOLUTION: You roll a number cube twice. Find P(odd, then not 1). Write the probability as a fraction in simplest form.
So far I have P odd = 6/12 or 1/2 then I think (then not 1) is 6/1
Algebra ->
Probability-and-statistics
-> SOLUTION: You roll a number cube twice. Find P(odd, then not 1). Write the probability as a fraction in simplest form.
So far I have P odd = 6/12 or 1/2 then I think (then not 1) is 6/1
Log On
Question 1081922: You roll a number cube twice. Find P(odd, then not 1). Write the probability as a fraction in simplest form.
So far I have P odd = 6/12 or 1/2 then I think (then not 1) is 6/12 - 2/12 = 4/12 or 1/3.
Am I correct? Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website!
First roll : odd.
Not sure why you have 6 out of 12.
There are only 6 possible outcomes.
Three of them are odd.
.
.
.
Second roll : not a 1.
Again six possible outcomes, five are not 1.
So together,
