SOLUTION: Recall that for use of a normal distribution as an approximation to the binomial distribution, the conditions np > 5 and nq > 5 must be met. For p = 0.2, compute the minimum sample

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Question 1081891: Recall that for use of a normal distribution as an approximation to the binomial distribution, the conditions np > 5 and nq > 5 must be met. For p = 0.2, compute the minimum sample size needed for use of the normal approximation. Round to the nearest whole number.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Plug p = 0.2 into the first inequality and solve for n

n%2Ap+%3E+5

n%2A0.2+%3E+5

%28n%2A0.2%29%2F0.2+%3E+5%2F0.2

n+%3E+25

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For the second inequality plug q = 1-p in first, then plug in p = 0.2, and solve for n

n%2Aq+%3E+5

n%2A%281-p%29+%3E+5

n%2A%281-0.2%29+%3E+5

n%2A0.8+%3E+5

%28n%2A0.8%29%2F0.8+%3E+5%2F0.8

n+%3E+6.25

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Intersecting the two inequalities n+%3E+25 and n+%3E+6.25 leads to just n+%3E+25, as this is the region they both share in common

So overall, the solution is n+%3E+25 where n is a positive whole number.

We'll need n to be larger than 25 in order to use a normal approximation.

The min sample size needed is 26