SOLUTION: Suppose that 55% of all adults in a certain community are obese and that 36% suffer from diabetes. If 14% of the adults in this community are both obese and suffering f

Algebra ->  Probability-and-statistics -> SOLUTION: Suppose that 55% of all adults in a certain community are obese and that 36% suffer from diabetes. If 14% of the adults in this community are both obese and suffering f      Log On


   



Question 1081864: Suppose that
55%
of all adults in a certain community are obese and that
36%
suffer from diabetes. If
14%
of the adults in this community are both obese and suffering from diabetes, what is the probability that a randomly chosen adult in this community is obese or suffers from diabetes (or both)?

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
p(A or B)=p(A)+p(B)-p(A and B)
=0.55+0.36-0.14=0.77. The 0.14 is subtracted to deal with double counting.