SOLUTION: Given the polynomial f(x)= x^4 -6x^3 +9x^2 +4x -12 , (I) factorize f(x) completely and hence find the x and y axes intercepts (II) state the x coordinates where the graph of

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Given the polynomial f(x)= x^4 -6x^3 +9x^2 +4x -12 , (I) factorize f(x) completely and hence find the x and y axes intercepts (II) state the x coordinates where the graph of       Log On


   



Question 1081854: Given the polynomial f(x)= x^4 -6x^3 +9x^2 +4x -12 ,
(I) factorize f(x) completely and hence find the x and y axes intercepts
(II) state the x coordinates where the graph of y=f(x) cuts the x-axis and where it touches the x-axis
(III) draw a sign diagram for f(x)
(IV) discuss the behaviour of f(x) as x = ∞ and as x = -∞
(V) sketch the graph of y=f(x), using the information obtained above.

Answer by josgarithmetic(39626) About Me  (Show Source):
You can put this solution on YOUR website!
Possible roots to try would be -6,-4,-3,-2,-1,1,2,3,4,6,12 (Rational Roots Theorem).
2   |    1   -6   9   4    -12
    |         2   -8  2     12
    |________________________________
        1    -4   1   6     0


3   |    1    -4    1     6
    |
    |          3    -3    -6
    |______________________________

         1    -1   -2     0



Partial factorizing gives f%28x%29=%28x-2%29%28x-3%29%28x%5E2-x-2%29.

The quadratic factor breaks into f being
f%28x%29=%28x-2%29%28x-3%29%28x-2%29%28x%2B1%29
highlight%28f%28x%29=%28x%2B1%29%28x-2%29%5E2%2A%28x-3%29%29

x-intercepts:
-1, 2, 3

y-intercept:
When x=0, y=-12.

Table of Signs:
Check inside each interval on x.
-
(infin, -1]
[-1, 2]
[2, 3]
[3, infinity)
-
You can determine the result in each interval on your own.


graph%28400%2C400%2C-5%2C5%2C-5%2C5%2Cx%5E4-6x%5E3%2B9x%5E2%2B4x-12%29

graph%28400%2C400%2C-3%2C4%2C-5%2C5%2Cx%5E4-6x%5E3%2B9x%5E2%2B4x-12%29

graph%28400%2C400%2C-12%2C12%2C-12%2C12%2Cx%5E4-6x%5E3%2B9x%5E2%2B4x-12%29