SOLUTION: Does 3 >= -6 equal o >= -9 ... if so why???? Would you divide both sides by 3....and if so...WHY????..... it has no variable left at this point. Please explain if there is a rul

Algebra ->  Inequalities -> SOLUTION: Does 3 >= -6 equal o >= -9 ... if so why???? Would you divide both sides by 3....and if so...WHY????..... it has no variable left at this point. Please explain if there is a rul      Log On


   



Question 1081810: Does 3 >= -6 equal o >= -9 ... if so why???? Would you divide both sides by 3....and if so...WHY????..... it has no variable left at this point. Please explain if there is a rule....do you look for factors???
How far do you break down an inequality???? These inequalities have different all real number sets. I have been given different answers on this.
Original problem.... 3(1-x) >= -3(x+2)

Found 2 solutions by Boreal, MathTherapy:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
3-3x >= -3x-6
-3x-3 >=-3x-6
-3 is greater than equal to -6
infinite solutions.
had it not been the case, no solutions.
check
x=0; 3>=-6
x=1; 0>=-9
x=-1; 6>=-3
x=-10; 33>=24.
When the variables disappear, look at what is left. If it is something like 3=3, infinite solutions, like this one.
If it is something like 2=4, then no solutions. IT IS NOT NECESSARY TO CONVERT IT TO 0>=-9. ONE COMPARES THE TWO SIDES IN INSTANCES WHEN THE VARIABLES ARE REMOVED FROM BOTH SIDES. THAT IS BOTH NECESSARY AND SUFFICIENT TO DRAW THE CONCLUSION THAT THERE ARE INFINITE OR NO SOLUTIONS.

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

Does 3 >= -6 equal o >= -9 ... if so why???? Would you divide both sides by 3....and if so...WHY????..... it has no variable left at this point. Please explain if there is a rule....do you look for factors???
How far do you break down an inequality???? These inequalities have different all real number sets. I have been given different answers on this.
Original problem.... 3(1-x) >= -3(x+2)
If you have an inequality that contains a variable, then you need to solve for that variable. When a value is obtained for that variable,
that value should be substituted into the ORIGINAL INEQUALITY to determine if that value SATISFIES or makes the INEQUALITY TRUE.
In this case, the variable x DISAPPEARS (resulted in a value of 0) from the left side of the INEQUALITY, in which case, you need to determine if the INEQUALITY is TRUE.
Let's look at this inequality.
3%281+-+x%29+%3E=+-+3%28x+%2B+2%29
3+-+3x+%3E=+-+3x+-+6 ------- Distributing
-+3x+%2B+3x+%3E=+-+6+-+3 ----- COLLECTING like-terms
Final answer: 0+%3E=+-+9. Is this TRUE? Yes, it is, and so, ANY VALUE that is given to x will ALWAYS, ALWAYS make this inequality TRUE.