SOLUTION: The average of four numbers is 18. If one of the four numbers, 25, is taken away, what is the average of the remaining three numbers?

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Question 108177: The average of four numbers is 18. If one of the four numbers, 25, is taken away, what is the average of the remaining three numbers?
Found 2 solutions by edjones, MathLover1:
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
18*4=72 sum of the 4 numbers
72-25=47 sum of 3 remaining numbers.
47/3=15 2/3 average of 3 numbers.
Ed

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!


Given: %28a+%2B+b+%2B+c+%2B+d%29%2F4+=+18 , a+=+25
%2825%2Bb%2Bc%2Bd%29+=18%2A4
%2825%2Bb%2Bc%2Bd%29+=+72
If 25 is taken away
%28b%2Bc%2Bd%29+=+72+-25
Then:
%28b%2Bc%2Bd%29+=+47