SOLUTION: y^2-6y-4x+17=0 write in standard form then identify the parts of the ellipse

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Question 1081769: y^2-6y-4x+17=0 write in standard form then identify the parts of the ellipse
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
It's not an ellipse, it's a parabola.
The x term is linear.
4x=y%5E2-6y%2B17
4x=%28y%5E2-6y%2B9%29%2B17-9
4x=%28y-3%29%5E2%2B8
x=%28y-3%29%5E2%2F4%2B2
Vertex at (2,3)
Opens to the right.
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