SOLUTION: a box contains 9 tickets numbered from 1 to 9 .if 3 tickets are drawn from the box one at a time find the probability they are alternatively either odd ,even,odd or even odd eben.

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Question 1081744: a box contains 9 tickets numbered from 1 to 9 .if 3 tickets are drawn from the box one at a time find the probability they are alternatively either odd ,even,odd or even odd eben.
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
5 odd and 4 even
o-e-o: 5/9*4/8*4/7=80/504 or 0.1587
e-o-e: 4/9*5/8*3/7=60/504=0.1190