SOLUTION: In​ 1997, a survey of 900 households showed that 150 of them use​ e-mail. Use those sample results to test the claim that more than​ 15% of households use​

Algebra ->  Probability-and-statistics -> SOLUTION: In​ 1997, a survey of 900 households showed that 150 of them use​ e-mail. Use those sample results to test the claim that more than​ 15% of households use​       Log On


   



Question 1081731: In​ 1997, a survey of 900 households showed that 150 of them use​ e-mail. Use those sample results to test the claim that more than​ 15% of households use​ e-mail. Use a 0.05 significance level. Use this information to answer the following questions.
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
p hat =0.167
Using standard hypothesis testing, z=(0.167-0.15)/sqrt{0.15*0.85/900); sqrt term is 0.0119
z=0.017/0.0119=1.43 fail to reject Ho; insufficient evidence that this is a significant difference at the 0.05 level.
p-value is 0.08 for a one way test.