You can
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can someone help me solve: given logb3 = 0.6826
and logb7 = 1.2091, evaluate logb21.
completely lost.
You need to know this basic rule of logarithms:
logb(X·Y) = logbX + logbY
and the fact that 21 = 3·7, to get
logb(3·7) = logb3 + logb7
then since you are given that
logb3 = 0.6826 and logb7 = 1.2091
logb(3·7) = logb3 + logb7 = 0.6826 + 1.2091 = 1.8917
Edwin