Question 108166: can anyone help me?:determine the horizontal asymptote of the graph of
B(t)=1200/1+34e^-0.125t. i have no idea how to solve this.
Answer by Fombitz(32388)   (Show Source):
You can put this solution on YOUR website! You can do it two ways.
Graphically or by analysis.
Let's do analysis.
As t gets large, since there is a -.125 coefficient to multiply t in the exponential, the exponential function drops quickly to zero.
Then function then looks like
 for large positive t.
Example: At t=100, B(t)=1199.848
I'm not sure of the context of this function, that is if t is always positive, like time.
If not, we can look at what happens when t becomes large in the negative direction.
In that case (-.125t) becomes very large, and the exponential function becomes very large.
 for large negative t.
Example: At t=-100, B(t)=.000132
There is a horizontal asymptote at y=1200.
And if it makes sense in your problem, there is also one at y=0.
Graphically it's easier to find the asymptotes,
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