Question 1081579: A submarine left the Azores and traveled
west. Three hours later an aircraft carrier
left traveling 3 mph faster in an effort to
catch up to it. After seven hours the aircraft
carrier finally caught up. Find the
submarine's average speed.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! A submarine left the Azores and traveled west.
Three hours later an aircraft carrier left traveling 3 mph faster in an effort to catch up to it.
After seven hours the aircraft, carrier finally caught up.
Find the submarine's average speed.
:
From the information given, we know
Sub travel time = 10 hrs
Car travel time = 7 hr
;
let s = sub speed
then
(s+3) = car speed
:
When carrier catches the sub, they each will have traveled the same distance
Write a distance equation; dist = time * speed
10s = 7(s+3)
10s = 7s + 21
10s - 7s = 21
3s = 21
s = 21/3
s = 7 mph is the speed of the sub
:
:
Check this, find the dist of each
10*7 = 70 mi
7(7+3) = 70 mi
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