SOLUTION: A man on his way to work encounters traffic lights A, B and C every morning. the lights work independently of one another and have probabilities 0.2, 0.6 and 0.3 respectively of st
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Question 1081413: A man on his way to work encounters traffic lights A, B and C every morning. the lights work independently of one another and have probabilities 0.2, 0.6 and 0.3 respectively of stopping the man every morning. Find the probability that the man on his way to work on Tuesday morning will be stopped by i. traffic lights A only ii. A and B only iii Exactly two of the traffic lights Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! i. 0.2*0.4*0.7=0.056
ii. 0.2*0.6*0.7=0.084
A and B: 0.084
A and C: 0.2*0.4*0.3=0.024
B and C: 0.8*0.6*0.3=0.144
They add to 0.252
