SOLUTION: Find Pk + 1 if Pk = 7 + 13 + 19 +...+[6(k - 1)+1] + (6k + 1) A.) 7 + 13 + 19 + �+[6(k - 1) + 1] + (6k + 1) + [6(k + 1) + 1] B.) 8 + 14 + 20 + �+[7(k

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Question 1081311: Find Pk + 1 if
Pk = 7 + 13 + 19 +...+[6(k - 1)+1] + (6k + 1)
A.) 7 + 13 + 19 + �+[6(k - 1) + 1] + (6k + 1) + [6(k + 1) + 1]
B.) 8 + 14 + 20 + �+[7(k - 1) + 1] + (7k + 1)
C.) 7 + 13 + 19 + �+(6k + 1)
C.) 7 + 13 + 19 + ...+[6(k - 1) + 1] + (6k +1) + (6k + 2)
Answer by ikleyn(52807)   (Show Source):
You can put this solution on YOUR website!
.
A)

There is a bunch of lessons on the Method of Mathematical induction in this site
    - Mathematical induction and arithmetic progressions
    - Mathematical induction and geometric progressions
    - Mathematical induction for sequences other than arithmetic or geometric
    - Proving inequalities by the method of Mathematical Induction
    - OVERVIEW of lessons on the Method of Mathematical induction

Also, you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic
"Method of Mathematical induction".

SOLUTION: Find Pk + 1 if Pk = 7 + 13 + 19 +...+[6(k - 1)+1] + (6k + 1) A.) 7 + 13 + 19 + �+[6(k - 1) + 1] + (6k + 1) + [6(k + 1) + 1] B.) 8 + 14 + 20 + �+[7(k - 1) + 1] + (7k + 1) C.) 7