SOLUTION: The equation of a parabola is given. y=−112x2−2x−1 What are the coordinates of the focus of the parabola?

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Question 1081288: The equation of a parabola is given.

y=−112x2−2x−1

What are the coordinates of the focus of the parabola?

Answer by MathTherapy(10556) About Me  (Show Source):
You can put this solution on YOUR website!
The equation of a parabola is given.
y=−112x2−2x−1
What are the coordinates of the focus of the parabola?
1)  Switch sides to: 112x%5E2+-+2x+-+1+=+y
2) Get the Xs on the LEFT side, and the constant on the RIGHT
3) Complete the square on the Xs
4) Get the equation in the CONIC FORM of a parabola with a VERTICAL axis, or in the form: %28x+-+h%29%5E2+=+4p%28y+-+k%29
5) Compare the 2 equations to determine the coordinates of the focus, which are: (h, k + p).

You should know what I'm talking about, but if you feel you don't, then you need to open a book, or check online.
Here's a link to a similar problem that you could use:
https://www.algebra.com/algebra/homework/Quadratic-relations-and-conic-sections/Quadratic-relations-and-conic-sections.faq.question.618495.html